Having trouble writing python code for custom remote for OpenLP

BillC

I'm trying to create a program to control OpenLp and eventually OBS and a digital mixer.

I'm stuck trying to communicate with Openlp via the http api, everything I try gives a response of 404.

The code below is just one example. Can anyone provide a clue as to what could be wrong.

I am using 2.4.6

# importing the requests library

import requests

# api-endpoint

URL = "http://127.0.0.1:4316/api/v2/controller/live-items"

# sending get request and saving the response as response object

r = requests.get(URL)

print ( r)

Output is: <Response [404]>

jednou

Did you try any other ip address, like another physical interface? Built-in web remote plugin works?

Dont know your use-case.. Did you try Bitfocus Companion? They have integration to almost any controllable piece of sw/hw used in live production.

BillC

jednou thanks for your reply.

I did try my local ip address assigned by the router, had same errors.

I can connect to the built-in web remote from my android phone without any issue.

Thinking my problem is either with how I am formatting my call to requests.get or simply an issues with requests.get that I don't understand.

I will not rule out Bitfocus, but want to investigate further a python solution before attempting a totally new path.

jednou

OK, if you are using 2.4.6, then response 404 to GET /api/v2/controller/live-items is completely valid.

You can either use v2.4.6 and endpoints described in:

http://api.openlp.io/api/openlp/plugins/remotes.html

Or use 2.9.* and use urls like /api/v2/... as described in:

https://gitlab.com/openlp/wiki/-/wikis/Documentation/http-api

BillC

So I switched to using endpoints described at http://api.openlp.io/api/openlp/plugins/remotes.html

I'm trying to move to the next service item, but have no success.

Tried:

import requests

URL = 'http://192.168.0.15:4316/api/service'

payload = {'action':'next'}

r = requests.get(URL, data=payload)

also:

import requests

URL = 'http://192.168.0.15:4316/api/service?next'

r = requests.get(URL)

and:

import requests

URL = 'http://192.168.0.15:4316/api/service?{next}'

r = requests.get(URL)

any help would be much appreciated

jednou

Next service item: /api/service/next

Next slide: /api/controller/live/next

BillC

jednou, thanks for your response, but I do know what endpoints to use.

My question is how to incorporate them into python code.

jednou

import requests

URL = "http://192.168.0.15:4316/api/service/next"

response = requests.get(URL)

print(response)

BillC

jednou, Thanks that is exactly what I needed. Works perfectly!

Now I can move to next and previous items in service.

Now I need help to jump to a specific item. I tried but failed with:

URL = 'http://127.0.0.1:4316/api/service/jump?{"request": {"id": 2}}'

r = requests.get(URL)

jednou

import requests

url = "http://127.0.0.1:4316/api/service/set?data={\"request\": {\"id\": 2}}"

response = requests.get(url)

print(response)